Module 01 · Quantitative Aptitude

Maths for SSC CGL

Complete chapter-wise coverage with formulas, shortcut tricks (Aditya Ranjan sir approach), worked examples, and practice questions. Tier I: 25 Qs · Tier II: 90 min paper.

25 Qs Tier I
100 Qs Tier II Paper-I
–0.5 Negative marking (T-I)
13 Chapters covered
Chapter 01

Number System

Types of Numbers

Natural Numbers (N)

1, 2, 3, 4 ... (counting numbers, starts at 1)

Whole Numbers (W)

0, 1, 2, 3 ... (natural + zero)

Integers (Z)

...-3, -2, -1, 0, 1, 2, 3... (positive + negative + 0)

Rational Numbers (Q)

p/q form where q≠0. Includes all integers, fractions, terminating & recurring decimals.

Irrational Numbers

√2, √3, π, e — cannot be expressed as p/q. Non-terminating, non-recurring.

Real Numbers (R)

Rational ∪ Irrational. All numbers on the number line.

Prime & Composite Numbers

Prime: Exactly 2 factors (1 and itself). 2 is the only even prime. 1 is neither prime nor composite.

Primes up to 100: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 — 25 primes total.

Divisibility Rules

DivisorRuleExample
2Last digit even (0,2,4,6,8)348 ✓
3Sum of digits divisible by 3123 → 1+2+3=6 ✓
4Last 2 digits divisible by 41324 → 24÷4 ✓
5Last digit 0 or 5745 ✓
6Divisible by both 2 and 3312 ✓
7Double last digit, subtract from rest; repeat if needed161 → 16-(2×1)=14 ✓
8Last 3 digits divisible by 81256 → 256÷8 ✓
9Sum of digits divisible by 9729 → 7+2+9=18 ✓
11(Sum of odd-position digits) – (Sum of even-position digits) = 0 or multiple of 111331 → (1+3)–(3+1)=0 ✓
25Last 2 digits divisible by 251475 → 75÷25 ✓

HCF & LCM

Key Relation
HCF × LCM = Product of two numbers
HCF (GCD)
  • Largest number that divides all given numbers
  • HCF of fractions = HCF of numerators / LCM of denominators
LCM
  • Smallest number divisible by all given numbers
  • LCM of fractions = LCM of numerators / HCF of denominators
⚡ Aditya Ranjan Trick

For "largest number dividing a, b, c leaving same remainder r" → HCF of (a−b), (b−c), (a−c). For "leaving remainders r₁, r₂ …" → HCF of (a−r₁), (b−r₂), …

Unit Digit Cyclicity

BaseCyclePattern
242,4,8,6,2,4,8,6...
343,9,7,1,3,9,7,1...
424,6,4,6...
747,9,3,1,7,9,3,1...
848,4,2,6,8,4,2,6...
0,1,5,61Always same digit
929,1,9,1... (odd→9, even→1)
⚡ Quick Method

To find unit digit of a^n: find (n mod cycle). If remainder=0, use last value in cycle. Example: 7^53 → 53 mod 4 = 1 → unit digit = 7¹ = 7

Practice — Number System

The HCF of two numbers is 11 and their LCM is 693. If one number is 77, what is the other?SSC CGL 2019 pattern

HCF × LCM = a × b → 11 × 693 = 77 × b → b = 7623/77 = 99

What is the unit digit of 3^75?Direct application of cyclicity

3 has cycle 4. 75 mod 4 = 3. 3rd in cycle [3,9,7,1] = 7
Chapter 02

Percentage

Core Formulas

Percentage
x% of y = (x × y) / 100
% Change
% Change = [(New − Old) / Old] × 100
% Increase then Decrease
Net % change = a + b + (ab/100) [use –b for decrease]

Fraction ↔ Percentage Conversions (Must memorise)

Fraction%Fraction%
1/250%1/714.28%
1/333.33%1/812.5%
1/425%1/911.11%
1/520%1/1010%
1/616.67%1/119.09%
2/366.67%3/475%
2/540%3/560%
4/580%5/683.33%

Key Relationships

If A is x% more than B → B is [x/(100+x)] × 100 % less than A
If A is x% less than B → B is [x/(100−x)] × 100 % more than A

⚡ Successive % Trick

Two successive discounts of a% and b% = Net discount = a + b − ab/100
Example: 20% then 10% = 20+10−2 = 28% net discount

Practice — Percentage

A number is increased by 20% and then decreased by 20%. Net change?Successive % application

Net = 20 + (−20) + (20×−20)/100 = 0 − 4 = −4% i.e. 4% decrease
Chapter 03

Profit & Loss

Fundamental Formulas

Profit %
Profit% = (Profit / CP) × 100
SP when profit%
SP = CP × (100 + P%) / 100
Loss %
Loss% = (Loss / CP) × 100
SP when loss%
SP = CP × (100 − L%) / 100
CP from SP
CP = SP × 100 / (100 + P%) OR CP = SP × 100 / (100 − L%)

Discount Formulas

Discount
Discount = Marked Price (MP) − Selling Price (SP)
Discount% = (Discount / MP) × 100
SP with discount
SP = MP × (100 − D%) / 100
Profit % on MP
P% = [(MP − CP) / CP] × 100

Dishonest Dealer / False Weight

⚡ Shortcut

Profit% = [(True weight − False weight) / False weight] × 100
If a dealer uses 900g weight instead of 1kg: P% = (1000−900)/900 × 100 = 11.11%

Two Items — Same CP/SP Situations

Selling 2 items at same SP, one at x% profit and other at x% loss → Always a loss of (x/10)² % = x²/100 %

Practice — Profit & Loss

A shopkeeper marks his goods 40% above cost price and gives 25% discount. Profit %?MP and discount problem

Let CP=100, MP=140, SP=140×0.75=105 → Profit = 5%

Two articles sold at Rs 990 each. One at 10% profit, other at 10% loss. Net result?Classic SSC trap

Loss = x²/100 % = 100/100 = 1% on total SP (1980). CP total = 900+1100=2000. Loss = 2000−1980 = Rs 20
Chapter 04

Simple & Compound Interest

Simple Interest

SI Formula
SI = (P × R × T) / 100
Amount
A = P + SI = P(1 + RT/100)

Compound Interest

CI Amount
A = P × (1 + R/100)ⁿ
CI
CI = A − P = P[(1 + R/100)ⁿ − 1]

Half-Yearly & Quarterly Compounding

TypeRate becomesTime becomes
Half-yearlyR/22n
QuarterlyR/44n
MonthlyR/1212n

Key SI vs CI Differences

For same P, R, T:
CI − SI (2 years) = P(R/100)²
CI − SI (3 years) = P(R/100)²(3 + R/100)

⚡ Effective Rate Trick

10% CI for 2 years = 10+10+(10×10)/100 = 21% effective rate. Use the successive % formula.

Practice — SI & CI

At what rate % CI, Rs 800 amounts to Rs 882 in 2 years?

882/800 = 1.1025 = (1+r)² → 1+r = 1.05 → r = 5%
Chapter 05

Ratio & Proportion

Key Concepts

Proportion
a:b = c:d → ad = bc (product of means = product of extremes)

Types of Ratios

Duplicate Ratio

a²:b² (square of ratio a:b)

Sub-duplicate

√a:√b

Triplicate

a³:b³

Componendo

(a+b):(a−b) from a:b

Dividendo

(a−b):b

Componendo-Dividendo

(a+b)/(a−b) = (c+d)/(c−d)

Partnership

Simple partnership: Profit ratio = ratio of capitals (same time)
Compound partnership: Profit ratio = Capital × Time

⚡ Partnership Trick

A invests ₹12000 for 6 months, B invests ₹8000 for 12 months. Profit ratio = (12000×6):(8000×12) = 72000:96000 = 3:4

Chapter 06

Time & Work

Core Approach

If A can do work in n days, A's 1-day work = 1/n. Assume total work = LCM of days for easier calculation.

Combined Work
A+B together finish in = (a×b)/(a+b) days

Pipes & Cisterns

Inlet pipe fills → positive work. Outlet pipe drains → negative work.
Net rate = Sum of all inlet rates − Sum of all outlet rates.

Work & Wages

⚡ Wages Trick

Wages are distributed in the ratio of work done. If A:B work ratio is 3:2, wages are also 3:2.

Problem: A can finish in 12 days, B in 15 days, C in 20 days. A and B work for 3 days, then C joins. How many more days?

Solution: LCM(12,15,20) = 60 = total work.
A's rate = 5/day, B's rate = 4/day, C's rate = 3/day
Work by A+B in 3 days = (5+4)×3 = 27
Remaining = 60−27 = 33
Rate of A+B+C = 5+4+3 = 12/day
More days = 33/12 = 2.75 days

Practice — Time & Work

A pipe fills a tank in 6 hours. A leak drains it in 12 hours. How long to fill with both?

Net rate = 1/6 − 1/12 = 2/12 − 1/12 = 1/12. Time = 12 hours
Chapter 07

Speed, Distance & Time

Core Formulas

Speed = Distance / Time
Distance = Speed × Time
Time = Distance / Speed

Unit Conversions

km/h → m/s: multiply by 5/18
m/s → km/h: multiply by 18/5

Trains

SituationDistance to cover
Train crosses a pole/manLength of train
Train crosses a platform/bridgeLength of train + Length of platform
Two trains same directionSum of lengths / |S1−S2|
Two trains opposite directionSum of lengths / (S1+S2)

Boats & Streams

Speed upstream
Speed upstream = Boat speed − Stream speed
Speed downstream
Speed downstream = Boat speed + Stream speed
⚡ Reverse Formula

Boat speed = (downstream + upstream) / 2
Stream speed = (downstream − upstream) / 2

Average Speed

Same distance at different speeds
Avg Speed = 2ab/(a+b) [harmonic mean, NOT arithmetic mean!]
⚡ Common Mistake Trap

Going 60 km/h, returning 40 km/h → Average ≠ 50. Average = 2×60×40/100 = 48 km/h

Chapter 08

Geometry

Lines & Angles

Supplementary Angles

Sum = 180°

Complementary Angles

Sum = 90°

Vertically Opposite

Always equal

Transversal

Alternate interior = equal (parallel lines). Co-interior = 180°.

Triangles

Sum of angles = 180°. Exterior angle = sum of two non-adjacent interior angles.

Important Triangle Properties

  • Centroid (G): Intersection of medians. Divides each median in 2:1 from vertex.
  • Incentre (I): Intersection of angle bisectors. Equidistant from all three sides.
  • Circumcentre (O): Intersection of perpendicular bisectors. Equidistant from all vertices.
  • Orthocentre (H): Intersection of altitudes.
  • For equilateral triangle: G, I, O, H all coincide.

Pythagoras Theorem & Triples

Pythagoras
a² + b² = c² (c = hypotenuse)

Common Pythagorean triples: (3,4,5), (5,12,13), (8,15,17), (7,24,25), (9,40,41) — memorise multiples too.

Circles

PropertyStatement
Angle at centreTwice the angle at circumference on same arc
Angles in same segmentEqual
Angle in semicircleAlways 90°
Cyclic quadrilateralOpposite angles sum to 180°
Tangent-radiusAlways perpendicular
Tangents from external pointEqual length
Chord-tangent angle= Angle in alternate segment (Tangent-Chord theorem)
Chapter 09

Mensuration

2D Shapes

ShapeAreaPerimeter
Square (side a)4a
Rectangle (l×b)l×b2(l+b)
Triangle½ × base × heighta+b+c
Equilateral △ (side a)(√3/4)a²3a
Circle (radius r)πr²2πr
Trapezium½(a+b)×ha+b+c+d
Rhombus (diagonals d1,d2)½×d1×d24×side
Parallelogrambase × height2(a+b)

3D Shapes

ShapeVolumeLateral SATotal SA
Cube (a)4a²6a²
Cuboid (l,b,h)lbh2h(l+b)2(lb+bh+hl)
Cylinder (r,h)πr²h2πrh2πr(r+h)
Cone (r,h,l)⅓πr²hπrlπr(r+l)
Sphere (r)⁴⁄₃πr³4πr²
Hemisphere (r)⅔πr³2πr²3πr²

Slant height of cone: l = √(r² + h²)

Chapter 10

Trigonometry

Trigonometric Ratios

Basic Ratios (SOH CAH TOA)
sin θ = P/H · cos θ = B/H · tan θ = P/B
cosec θ = H/P · sec θ = H/B · cot θ = B/P

Standard Angle Values

θsincostancosecseccot
0101
30°1/2√3/21/√322/√3√3
45°1/√21/√21√2√21
60°√3/21/2√32/√321/√3
90°1010
⚡ sin Memory Trick

sin 0°, 30°, 45°, 60°, 90° = √(0/4), √(1/4), √(2/4), √(3/4), √(4/4) = 0, 1/2, 1/√2, √3/2, 1

Key Identities

sin²θ + cos²θ = 1
1 + tan²θ = sec²θ
1 + cot²θ = cosec²θ

Heights & Distances

Angle of Elevation: Looking UP. tan θ = height / horizontal distance
Angle of Depression: Looking DOWN. Angle of depression = angle of elevation (alternate angles)

Chapter 11

Algebra

Important Identities

(a+b)² = a²+2ab+b²
(a−b)² = a²−2ab+b²
(a+b)(a−b) = a²−b²
(a+b)³ = a³+3a²b+3ab²+b³
(a−b)³ = a³−3a²b+3ab²−b³
a³+b³ = (a+b)(a²−ab+b²)
a³−b³ = (a−b)(a²+ab+b²)
a³+b³+c³−3abc = (a+b+c)(a²+b²+c²−ab−bc−ca)

If a+b+c = 0, then a³+b³+c³ = 3abc

Key SSC CGL Algebra Questions

⚡ x + 1/x = k type

If x + 1/x = 3:
x² + 1/x² = (x+1/x)² − 2 = 9−2 = 7
x³ + 1/x³ = (x+1/x)³ − 3(x+1/x) = 27−9 = 18
x⁴ + 1/x⁴ = (x²+1/x²)² − 2 = 49−2 = 47

Chapter 12

Mixture & Alligation

Rule of Alligation

Cheaper : Dearer = (Mean price − Cheaper price) : (Dearer price − Mean price)

⚡ Cross Method

Draw a cross. Write cheaper (c) at top-left, dearer (d) at top-right, mean (m) in centre.
Ratio = (d−m) : (m−c)
Example: Mix ₹60/kg and ₹90/kg to get ₹80/kg
Ratio = (90−80):(80−60) = 10:20 = 1:2

Repeated Dilution

After n replacements
Remaining pure = P × (1 − r/V)ⁿ
(P=initial, r=removed each time, V=total volume)
Chapter 13

Data Interpretation

Types of DI Questions

Bar Charts

Compare values, find % change between years, ratio between categories.

Line Graphs

Find trends, % increase/decrease, max/min rate of change.

Pie Charts

Central angle = (value/total)×360. % share = (value/total)×100.

Tables

Row/column sums, averages, percentage comparisons across rows/columns.

DI Approach

  • Read all questions first, then analyse the chart
  • Approximate: 33% ≈ ⅓, 25% = ¼ — use fractions for speed
  • For % change: (New−Old)/Old×100. Check sign (increase/decrease)
  • For ratios: simplify before calculating
  • Don't calculate exact values if options are far apart — estimate
⚡ Speed Tip

For Pie chart with total = 1200: 30° slice = (30/360)×1200 = 100. Always: (degrees/360) × total.